Threaded Mode | Linear Mode

flipper · 02-04-2010, 01:34 AM

Va salut. Am intampinat niste probleme in php, dar nu ma descurajez. Vreau sa invat, sa stiu unde gresesc. Si sper sa evoluez cu ajutorul vostru.

am pagina.php, urmatoarele:

PHP Code:

<?php require("php/functii.php"); ?>
lorem ipsum    <?php echo '$variabila' ?> sit amet 

in php/functii.php , am urmatorul cod:

PHP Code:

<?php
$variabila{
<div id="logo">
<h1><a href="#">site.ro</a></h1>
<h2><a href="#">sloganul</a></h2>
</div>
};
?>

unde gresesc? imi tot da eroarea

Code:

Parse error: syntax error, unexpected '<' in /home/site/public_html/script/php/functii.php on line 3

Va multumesc anticipat.
Florin M.

~~Bogdan2901~~ · 02-04-2010, 01:53 AM

Pune te rog codul integral... Ce sa intelegem noi din $variabila{ } ?? Daca vrei ca aceea variabila sa iti afiseze ce ai pui intre acolade, pui $variabila = 'ce sa-ti afiseze';

alleeex · (This post was last modified: 02-04-2010 02:03 AM by alleeex.)

<?php require("php/functii.php"); ?>
lorem ipsum <?php echo '$variabila' ?> sit amet
?>

Sterge asta.

flipper · 02-04-2010, 02:03 AM

ideea este ca nu stiu sa fac, tocmai de aceea va intreb.

asta este pagina functii.php

PHP Code:

<?php
//afisarea <div id="logo">
$variabila'
<div id="logo">
<h1><a href="#">site.ro</a></h1>
<h2><a href="#">sloganul</a></h2>
</div>
';

?>

iar asta este pagina index.php

PHP Code:

<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<title>Titlul</title>
<meta name="keywords" content="" />
<meta name="description" content="" />
<link href="default.css" rel="stylesheet" type="text/css" />
</head>
<body>[b]<?php require("php2324/functii.php"); ?>[/b]
<div id="dfgdfg">
    <div id="gt34g4">
        [b]<?php echo '$logo' ?>[/b]
     <br>  meniul
    </div>
    <div id="dvsdv">
        <div id="sdvsdv">
            <div id="dsvdsds">
                <div class="45">
                    <h2 class="sdewew"><a href="#">Detalii livrare</a></h2>
                    <div class="wefb">
                        <p><img src="images/img02.jpg" alt="#"  /></p>
                        
Modalitatea de livrare utilizata de site.ro este livrarea la adresa specificata de dumneavoastra.

                    </div>
                </div>
            </div>
            <div id="345">
                <ul>
                    <li id="g34">
                        <h2>Cauti un produs?</h2>
                        <form method="get" action="">
                            <fieldset>
                            <input type="text" id="cauta-text" name="s" value="" />
                            <input type="submit" id="cauta-buton" value="Cauta" />
                            </fieldset>
                        </form>
                    </li>
                    <li>
                        <h2>Categorii</h2>
                        <ul>
                            <li><a href="#">Categoria 1</a></li>
                            <li><a href="#">Categoria 2</a></li>
                            <li><a href="#">Categoria 3</a></li>
                            <li><a href="#">Categoria 4</a></li>
                        </ul>
                    </li>
                </ul>
            </div>
        
        </div>
    </div>
</div>
</body>
</html> 

FinalDestiny · 02-04-2010, 02:07 AM

Nu am inteles ce vrei sa faci tu acolo dar :

1.
$variabila'
<div id="logo">
<h1><a href="#">site.ro</a></h1>
<h2><a href="#">sloganul</a></h2>
</div>
';

wtf e asta? Ce vrei sa faci aici? $variabila sa devina <div id = "logo" bla bla? pai pune $variabila = '<div bla bla bla bla';
Daca vrei sa concatenezi 2 stringuri, le concatenezi cu . ...Spre exemplu $variabila1.$variabila2
Apoi echo '$logo' . Nu sunt necesare ' ' , pune direct echo $logo

~~Bogdan2901~~ · (This post was last modified: 02-04-2010 02:14 AM by Bogdan2901.)

FinalDestiny.... e eroare la sintaxa. Trebuia sa puna un " = " . Cum i-am zis..

$variabila = '<div......' ;

Si NU e nevoie sa dai un echo... poti pune direct include('php/functii.php'); in locul unde vrei sa iti apara.

flipper · 02-04-2010, 06:01 AM

Multumesc, maestre Bogdan2901.

~~Bogdan2901~~ · 02-04-2010, 06:09 AM

flipper Wrote:Multumesc, maestre Bogdan2901.

Cu placere ! Rolleyes

Asa, mor de curiozitate, unde ai vazut sintaxa cu $variabila{ } sau $variabila' '

Oricum, abia asteptam intrebari noi Big Grin

flipper · (This post was last modified: 02-04-2010 06:18 AM by flipper.)

Era pe un site de tutoriale php in romana. Nu mai tin minte adresa, din pacate. Intrebari mai am, bineinteles. vezi mai sus in Invatam Net - Forum webmasteri / Web development / Programare / . Omul cat traieste invata, iar eu am de gand sa traiesc mult, sa deprind tainele php-ului.

flipper · (This post was last modified: 02-04-2010 10:43 PM by flipper.)

Tot la extragerea variabilelor din fisiere externe am ramas.. Am introdus in baza de date titlul, descrierea, numele site-ului, sloganul etc.

in fisierul index.php, am asa

PHP Code:

<?php include("admin/functii.php"); ?>

<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<title><?php echo $settings['titlu']; ?></title>
<meta name="keywords" content="<?php echo $settings['keywords']; ?>" />
<meta name="description" content="<?php echo $settings['description']; ?>" />
<meta name="author" content="<?php echo $settings['author']; ?>" />
<link href="default.css" rel="stylesheet" type="text/css" /> 

in functii.php, am urmatoarele:

PHP Code:

<?php
// procedeul prin care afisez paginile intr-una singura
$show=$_GET['show'];
//datele de conectare la baza de date
$host="localhost"; //modifica
$username="baza_eu"; //modifica
$password="parola"; //modifica
$db_name="baza_scriptshop"; //modifica
$tbl_setari="setari"; // Table name
$tbl_categoria="categoria"; // Table name
$tbl_produse="produse"; // Table name
mysql_connect("$host", "$username", "$password")or die("nu ma pot conecta la server");
mysql_select_db("$db_name")or die("nu ma pot conecta la baza de date");
$settings="SELECT * FROM $tbl_setari";
$site_setari=mysql_query($settings);
?>

cand ii dau view source, imi arata

PHP Code:

<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<title>S</title>
<meta name="keywords" content="S" />
<meta name="description" content="S" />
<meta name="author" content="S" />
<link href="default.css" rel="stylesheet" type="text/css" /> 

Imi vine rau cand vad numai S. Nici macar nu sunt sasait Smile

. Unde gresesc?

sqlul pentru setarile site-ului arata asa..

PHP Code:

CREATE TABLE IF NOT EXISTS `setari` (
  `titlu` varchar(255) NOT NULL,
  `nume` varchar(255) NOT NULL,
  `slogan` varchar(255) NOT NULL,
  `url` varchar(255) NOT NULL,
  `description` varchar(255) NOT NULL,
  `keywords` varchar(255) NOT NULL,
  `author` varchar(255) NOT NULL
) ENGINE=MyISAM DEFAULT CHARSET=latin1;

--
-- Dumping data for table `setari`
--

INSERT INTO `setari` (`titlu`, `nume`, `slogan`, `url`, `description`, `keywords`, `author`) VALUES
('titlul siteului', 'numele site-ului', 'sloganul', 'urlul', 'descriptiaaaaa lorem ipsum', 'kei1 chei 2 chei 3', 'autor adica eu florin matei'); 